\(\mathop {\lim }\limits_{x \to 2} \frac{{{x^2} + 3x - 10}}{{3{x^2} - 5x - 2}}\)
Giải chi tiết:
\(\mathop {\lim }\limits_{x \to 2} \frac{{{x^2} + 3x - 10}}{{3{x^2} - 5x - 2}}\)\( = \mathop {\lim }\limits_{x \to 2} \frac{{\left( {x - 2} \right)\left( {x + 5} \right)}}{{\left( {x - 2} \right)\left( {3x + 1} \right)}}\) \( = \mathop {\lim }\limits_{x \to 2} \frac{{x + 5}}{{3x + 1}} = \frac{7}{7} = 1\).
Chọn B.