Cho hàm số \(f\left( x \right) = \left\{ \begin{array}{l}{x^2} - 3x + 1\,\,\,\,khi\,\,\,x < 2\\5x - 3\,\,\,\,\,\,\,\,\,\,\,\,\,\,khi\,\,\,x \ge 2\end{array} \right.\,\,\,\,\,,\) tính \(\mathop {\lim }\limits_{x \to {2^ - }} f\left( x \right)\).
Giải chi tiết:
\(\mathop {\lim }\limits_{x \to {2^ - }} f\left( x \right) = \mathop {\lim }\limits_{x \to {2^ - }} \left( {{x^2} - 3x + 1} \right) = {2^2} - 3.2 + 1 = - 1\)
Chọn C.