\(\mathop {\lim }\limits_{x \to 2} \frac{{2x - {x^2}}}{{{x^2} - 5x + 6}}\)
Giải chi tiết:
\(\mathop {\lim }\limits_{x \to 2} \frac{{2x - {x^2}}}{{{x^2} - 5x + 6}}\) \( = \mathop {\lim }\limits_{x \to 2} \frac{{x\left( {2 - x} \right)}}{{\left( {x - 2} \right)\left( {x - 3} \right)}}\) \( = \mathop {\lim }\limits_{x \to 2} \frac{{ - x}}{{x - 3}} = \frac{{ - 2}}{{ - 1}} = 2\).
Chọn A.