[LỜI GIẢI] Tìm x biết: la);( 2x-130 ):4 + 213 = 5^2 + 193b)( 5^2 + 3^2 )x + ( 5^2-3^2 )x-50 = 10^2 - Tự Học 365
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Tìm x biết: la);( 2x-130 ):4 + 213 = 5^2 + 193b)( 5^2 + 3^2 )x + ( 5^2-3^2 )x-50 = 10^2

Tìm x biết: 
la);( 2x-130 ):4 + 213 = 5^2 + 193b)( 5^2 + 3^2 )x + ( 5^2-3^2 )x-50 = 10^2

Câu hỏi

Nhận biết

Tìm \(x\) biết:

\(\begin{array}{l}a)\;\left( {2x-130} \right):4 + 213 = {5^2} + 193\\b)\left( {{5^2} + {3^2}} \right)x + \left( {{5^2}-{3^2}} \right)x-50 = {10^2}\end{array}\)


Đáp án đúng: B

Lời giải của Tự Học 365

Giải chi tiết:

\(\begin{array}{l}a)\,\,\;\left( {2x-130} \right):4 + 213 = {5^2} + 193\\\,\,\,\,\,\,\left( {2x-130} \right):4 + 213 = 25 + 193\\\,\,\,\,\,\,\left( {2x-130} \right):4 + 213 = 218\\\,\,\,\,\,\,\left( {2x-130} \right):4\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = 218 - 213\\\,\,\,\,\,\,\left( {2x-130} \right):4\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = 5\\\,\,\,\,\,\,\,2x-130\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = 5.4\\\,\,\,\,\,\,\,2x-130\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = 20\\\,\,\,\,\,\,\,2x\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = 20 + 130\\\,\,\,\,\,\,2x\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = 150\\\,\,\,\,\,\,\,\,\,x\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = 150:2\\\,\,\,\,\,\,\,\,x\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = 75\end{array}\)                                                 

\(\begin{array}{l}b)\,\,\left( {{5^2} + {3^2}} \right)x + \left( {{5^2}-{3^2}} \right)x-50 = {10^2}\\\,\,\,\,\,\,\,\left( {25 + 9} \right)x + \left( {25 - 9} \right)x - 50 = {10^2}\\\,\,\,\,\,\,\,\,34x + 16x - 50\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = {10^2}\\\,\,\,\,\,\,\,\,50x - 50\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = 100\\\,\,\,\,\,\,\,\,50x\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = 100 + 50\\\,\,\,\,\,\,\,\,50x\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = 150\\\,\,\,\,\,\,\,\,\,\,\,\,\,\,x\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = 150:50\\\,\,\,\,\,\,\,\,\,\,\,\,\,x\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = 3.\\\\\\\\\end{array}\)

Chọn B.

 

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