Danh sách câu hỏi
[mathop lim limitsx to 1 căn 5 - x^3 - căn [3]x^2 + 7x^2 - 1 - Tự Học 365] \(\mathop {\lim }\limits_{x \to 1} \frac{{\sqrt {5 - {x^3}} - \sqrt[3]{{{x^2} + 7}}}}{{{x^2} - 1}}\)
[mathop lim limitsx to 1 căn [3]3x - 2 - căn 4x^2 - x - 2 x^2 - 3x + 2 - Tự Học 365] \(\mathop {\lim }\limits_{x \to 1} \frac{{\sqrt[3]{{3x - 2}} - \sqrt {4{x^2} - x - 2} }}{{{x^2} - 3x + 2}}\)
[mathop lim limitsx to 1 căn 1 + 3x + căn [3]1 - 9x( x - 1 )^2 - Tự Học 365] \(\mathop {\lim }\limits_{x \to 1} \frac{{\sqrt {1 + 3x} + \sqrt[3]{{1 - 9x}}}}{{{{\left( {x - 1} \right)}^2}}}\)
[mathop lim limitsx to 0 căn [3]1 + 3x - 1 - x căn 1 - x x^3 + x^2 - Tự Học 365] \(\mathop {\lim }\limits_{x \to 0} \frac{{\sqrt[3]{{1 + 3x}} - 1 - x\sqrt {1 - x} }}{{{x^3} + {x^2}}}\)
[mathop lim limitsx to 2 căn [3]x + 6 - căn [4]7x + 2x - 2 - Tự Học 365] \(\mathop {\lim }\limits_{x \to 2} \frac{{\sqrt[3]{{x + 6}} - \sqrt[4]{{7x + 2}}}}{{x - 2}}\)
[mathop lim limitsx to 0 d căn [n]1 + ax - 1 căn [m]1 + bx - 1( ab ne 0mn ge 2 ) - Tự Học 365] \(\mathop {\lim }\limits_{x \to 0} \dfrac{{\sqrt[n]{{1 + ax}} - 1}}{{\sqrt[m]{{1 + bx}} - 1}}\,\,\,\left( {ab \ne 0,m,n \ge 2} \right)\)
[mathop lim limitsx to 0 căn 1 + alpha x . căn [3]1 + beta x. căn [4]1 + gamma x - 1x( alpha beta g - Tự Học 365] \(\mathop {\lim }\limits_{x \to 0} \frac{{\sqrt {1 + \alpha x} .\sqrt[3]{{1 + \beta x}}.\sqrt[4]{{1 + \gamma x}} - 1}}{x}\,\,\,\,\left( {\alpha \beta \gamma \ne 0} \right)\)
[mathop lim limitsx to 0 căn [m]1 + ax. căn [n]1 + bx - 1x( ab ne 0mn ge 2 ) - Tự Học 365] \(\mathop {\lim }\limits_{x \to 0} \frac{{\sqrt[m]{{1 + ax}}.\sqrt[n]{{1 + bx}} - 1}}{x}\,\,\,\,\left( {ab \ne 0,m,n \ge 2} \right)\)
[mathop lim limitsx to 2 x^2020 - 2^2020x^2021 - 2^2021 - Tự Học 365] \(\mathop {\lim }\limits_{x \to 2} \frac{{{x^{2020}} - {2^{2020}}}}{{{x^{2021}} - {2^{2021}}}}\)
[mathop lim limitsx to 1 2x - căn 3x + 1 x^2 - 1 - Tự Học 365] \(\mathop {\lim }\limits_{x \to 1} \frac{{2x - \sqrt {3x + 1} }}{{{x^2} - 1}}\)
[mathop lim limitsx to 1 2x - căn 3x + 1 x^2 - 1 - Tự Học 365] \(\mathop {\lim }\limits_{x \to 1} \frac{{2x - \sqrt {3x + 1} }}{{{x^2} - 1}}\)
[mathop lim limitsx to 1 căn 3x + 1 - căn x + 3 x^3 - 1 - Tự Học 365] \(\mathop {\lim }\limits_{x \to 1} \frac{{\sqrt {3x + 1} - \sqrt {x + 3} }}{{{x^3} - 1}}\)
[mathop lim limitsx to 1 căn x^3 + 3x - 2 căn x^2 + x + 7 - 3 - Tự Học 365] \(\mathop {\lim }\limits_{x \to 1} \frac{{\sqrt {{x^3} + 3x} - 2}}{{\sqrt {{x^2} + x + 7} - 3}}\)
[mathop lim limitsx to 0 căn x^2 + 1 + 2 căn x + 4 - 5x - Tự Học 365] \(\mathop {\lim }\limits_{x \to 0} \frac{{\sqrt {{x^2} + 1} + 2\sqrt {x + 4} - 5}}{x}\)
[mathop lim limitsx to 2 2x - x^2x^2 - 5x + 6 - Tự Học 365] \(\mathop {\lim }\limits_{x \to 2} \frac{{2x - {x^2}}}{{{x^2} - 5x + 6}}\)
